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| grondilu | Hello. Please look at this gist.github.com/grondilu/ebceff32e...fdb4516f24 and tell me what I am missing. | 03:30 | |
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| grondilu | basically I'm trying to catch a pattern in a multiline string but the regex grabs all the trailing newlines. | 03:31 | |
| m: say grammar { rule TOP { ^ <line>+ $ }; rule line { <.alpha>+ } } .parse: "foo\n" | 03:37 | ||
| camelia | ｢foo ｣ line => ｢foo ｣ |
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| grondilu | how can I extract "foo" and not "foo\n"? | 03:38 | |
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| grondilu | in a nutshell I want to parse a file with blocks of text separated by empty lines. | 03:39 | |
| that can't work as I've tried if the regex catches trailing newlines. | 03:40 | ||
| guifa | I would use token instead | 03:42 | |
| or change <ws> to be \h | |||
| so | 03:43 | ||
| say grammar { rule TOP { <line> %% \n }; rule line { <.alpha>+ } } .parse: "foo\nbar\nxyz\n" | 03:44 | ||
| m: say grammar { rule TOP { <line> %% \n }; rule line { <.alpha>+ } } .parse: "foo\nbar\nxyz\n" | |||
| camelia | ===SORRY!=== Error while compiling <tmp> Missing quantifier on the left argument of %% at <tmp>:1 ------> say grammar { rule TOP { <line> %%<HERE> \n }; rule line { <.alpha>+ } } .parse: |
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| guifa | m: say grammar { rule TOP { <line>+ %% \n }; rule line { <.alpha>+ } } .parse: "foo\nbar\nxyz\n" | ||
| camelia | Nil | ||
| guifa | m: say grammar { token TOP { <line>+ %% \n }; token line { <.alpha>+ } } .parse: "foo\nbar\nxyz\n" | 03:45 | |
| camelia | ｢foo bar xyz ｣ line => ｢foo｣ line => ｢bar｣ line => ｢xyz｣ |
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| grondilu tries | |||
| grondilu fails | 03:47 | ||
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| grondilu | m: say grammar { token TOP { <line>+ %% \n }; token line { <.alpha>+ } } .parse: "foo\n\nbar\n\nxyz\n" | 03:49 | |
| camelia | Nil | ||
| grondilu | there is no empty line in "foo\nbar" | ||
| ugexe | <.alpha>* | 03:55 | |
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